如何在java中设置y/n循环？

Question

我有一个程序，它是一个回文检查器，它接受一个输入，将其反转，并检查原始输入是否等于反转。我正试图在程序中得到一个y/n循环，以检查用户是否想要输入另一个回文。这是我的代码：

  public static void main(String[] args){
        Scanner scan = new Scanner(System.in);
        String controller = "y";
    do {

        System.out.println("Enter a palindrome!");
        String input = scan.nextLine();
        String original = input;
        input = input.replaceAll("\\s", "");
        int len = input.length();
        char[] charArray = new char[len];
        char[] charArray2 = new char[len];

        for(int i = 0; i < len; i++){
            charArray2[i] = input.charAt(i);
        }
        for(int j = 0; j < len; j++){
            charArray[j] = charArray2[len-1-j];
        }
        String palindrome = new String(charArray);
        if(palindrome.equals(input)){
            System.out.println(palindrome);
            System.out.println(original + " is a palindrome!\nWould you like to test another palindrome? (y/n)");
        }else{
            System.out.println(palindrome);
            System.out.println(original + " is not a palindrome!\nWould you like to test another palindrome? (y/n)");

        }
        scan.next(controller);

    }while(controller.equalsIgnoreCase("y"));

    }

这是我得到的输出：

Enter a palindrome!
was it a cat i saw
wasitacatisaw
was it a cat i saw is a palindrome!
Would you like to test another palindrome? (y/n)
y
Enter a palindrome!

 is a palindrome!
Would you like to test another palindrome? (y/n)
y
Enter a palindrome!

 is a palindrome!
Would you like to test another palindrome? (y/n)
y
Enter a palindrome!

 is a palindrome!
Would you like to test another palindrome? (y/n)
y
Enter a palindrome!

 is a palindrome!
Would you like to test another palindrome? (y/n)
y
Enter a palindrome!

 is a palindrome!
Would you like to test another palindrome? (y/n)
y

我不知道如何让它等待另一个条目并测试该条目。任何帮助都会很好

Answer 1

好的，我重新修改了你的代码，你离我不远了。 Here is a pastebin link使用我的代码

public static void main(String[] args) {
    String checker = "y"; //set checker to ensure the first cycle

    while(checker.equalsIgnoreCase("y")) { // check for correct phrase
        System.out.println("Enter a string to check!"); // inital message
        Scanner reader = new Scanner(System.in);        // read first line
        String input = reader.nextLine();
        if (isPalindrome(input)) {                      // check input for palindrome
            System.out.println(input + " is a Palindrome!");
        } else {
            System.out.println(input + " is not a Palindrome!");
        }
        System.out.println("Do you want to enter another string? y/n");
        checker = reader.nextLine();                    // set checker to response for next cycle
    }
    System.out.println("Ok bye :)");                    // death message
}


private static boolean isPalindrome(String s){
    String reverse = "";                            // create string for later comparison

    for (int i = 0; i < s.length(); i++) {
        reverse+=s.trim().charAt(s.length()-i-1);   // reverse the string
    }
    return reverse.equalsIgnoreCase(s);             // return boolean ignoring case
}

我真的没有改变那么多：

• 我检查函数中的回文以获得更好的可读性
• 使用字符串而不是字符[]。这样处理用户输入和一般文本通常更好

编辑： 我的输出：

Enter a string to check!
hey
hey is not a Palindrome!
Do you want to enter another string? y/n
y
Enter a string to check!
brb
brb is a Palindrome!
Do you want to enter another string? y/n
n
Ok bye :)

Process finished with exit code 0